What is the chance that a leap year, selected at random, will contain fifty three Sundays ?

\frac{6}{7}

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\frac{2}{7}

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\frac{4}{7}

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\frac{3}{7}

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Solution

The correct option is B $\frac{2}{7}$
$\begin{matrix} l e a p y e a r = 366 d a y s = 53 \times 7 + 2 d a y s o b a b i l i t y o f 53 s u n d a y s = \frac{2}{7} \end{matrix}$

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