What is the change in hybridization of oxygen atom associated with carbon in the zone of reduction?

It changes from sp to sp²

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It changes from sp² to sp

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It changes fromsp² to sp³

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No change

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Solution

The correct option is A
It changes from sp to sp²

‘O’ in ‘CO’ is ‘sp’ hybridized because one of the lone pairs in oxygen is donated to carbon whereas in $C O_{2}$ both the lone pairs on oxygen remain intact without participating in bonding thus ‘O’ in $^{'} C O_{2}^{'}$ are $s p^{2}$ hybridized.

$F e_{2} O_{3} + 3 C O \to 2 F e + 3 C O_{2}$

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{s p}^{3}

{s p}^{2}

s p

In a chemical change from $P C l_{3}$ $\to$ $P C l_{5}$ the hybrid state of P changes from :

C_{2} H_{2} - -- \to C_{2} H_{4} - -- \to C_{2} H_{6}

s p^{3}

s p^{2}

s p

s p^{3} \to s p^{2} \to s p

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