What is the change in oxidation state of Fe (Iron) in the preparation reaction of Nitrogen Monoxide ( $N O$ )?

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Solution

The correct option is A 1
$2 N a N O_{2} + 2 F e S O_{4} + 3 H_{2} S O_{4} \to F e_{2} (S O_{4})_{3} + 2 N a H S O_{4} + 2 H_{2} O + 2 N O$
Oxidation state of Fe in $F e S O_{4}$ is +2 and the oxidation state of $F e_{2} (S O_{4})_{3}$ is +3. So the net change in the oxidation state of Iron is 1

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