Question

What is the change in potential energy of the soap film formed on a frame of area $4\times {10}^{-3}{m}^2$, if the area of the film is reduced to half? (surface tension $=40\times {10}^{-3}N/m$)

• A. $32\times {10}^{-5}J$
• B. $16\times {10}^{-5}J$
• C. $8\times {10}^{-5}J$
• D. $16\times {10}^{-3}J$

Answer 1

The correct option is B $16\times {10}^{-5}J$