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B
O−−O=O+
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C
O=O−−O+
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D
O−=O+−O
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Solution
The correct option is AO=O+−O− Let us consider the ozone molecule (O3). The Lewis structure of O3 may be drawn as:
The atoms have been numbered as 1, 2 and 3. The formal charge on:
The central O atom marked 1 =6−2−12(6)=+1
The end O atom marked 2 =6−4−12(4)=0
The end O atom marked 3 =6−6−12(2)=−1
Hence, we represent O3 along with the formal charges as follows: