What is the chief product obtained when n-butane is treated with bromine in the presence of light at $130^{\circ} C$

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Solution

The correct option is A

Remember Bromination of alkane.

$C H_{3} - C H_{2} - C H_{2} - C H_{3} + B r_{2} h ν \to$

2-Bromobutane is the main product because $2^{\circ}$ carbonium ion is more stable than $1^{\circ}$ .

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Similar questions

130^{\circ} C

What is the chief product obtained when n-butane is treated with bromine in the presence of light at $130^{\circ} C$

H C l

C H_{3} - C H_{2} - C H_{2} - C H (B r) - C H_{3}

C H_{3} - C H_{2} - C H_{2} - C H = C H_{2}

E_{2}

B r - C H_{2} - C H_{2} - C H_{3}

100^{\circ} C

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