What is the coefficient of $x^{3}$ for the polynomial $x^{6} + 3 x^{5} - 4 x^{3} + 2 x = 0$ ?

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Solution

The correct option is B $- 4$
Given, $x^{6} + 3 x^{5} - 4 x^{3} + 2 x = 0$
The numerical values of the terms in a polynomial are called coefficients of the polynomial.
So, $- 4$ is the coefficient of $x^{3}$ .

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Similar questions

x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 = 0

2

x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 = 0

x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 = 0

f (x) = x^{6} - 3 x^{5} + 4 x^{3} + 3 x^{2} + 4 \Rightarrow f (x)

\frac{x^{3} + 2 x + 1}{5} - \frac{7}{2} x^{2} - x^{6}

x^{6}

\frac{x^{3} + 2 x + 1}{5} - \frac{7}{2} x^{2} - x^{6}

x^{3}

x^{6}

3 x^{2} y^{3} + 5 x y^{7} - x^{6}

3 x^{5} - 4 x^{3} + 2

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