Question

What is the complementary angle of [2 MARKS]

(a) ${65}^{\circ }$
(b) ${32}^{\circ }$

Answer 1

Each Part: 1 Mark

Sum of complementary angle is equal to ${90}^{\circ }$.

Therefore complementary angle of

(a) ${65}^{\circ }$
$\Rightarrow {90}^{\circ }-{65}^{\circ }={25}^{\circ }$

(b) ${32}^{\circ }$
$\Rightarrow {90}^{\circ }-{32}^{\circ }={58}^{\circ }$