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Byju's Answer
Standard XII
Chemistry
Raoult's Law
What is the c...
Question
What is the composition of the vapour which is in equilibrium at
30
∘
C
with a benzene-toluene solution with a mole fraction of benzene of
0.40
?
and with a mole fraction of benzene of
0.60
?
[
P
∘
b
=
119
torr and
P
∘
t
=
37
torr]
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Solution
We know
Y
B
=
X
B
P
B
X
t
P
t
+
X
B
P
B
a
)
Y
B
=
0.40
×
119
0.40
×
119
+
0.60
×
37
=
0.682
Now,
Y
t
=
X
t
P
t
X
t
P
t
+
X
B
P
B
Y
t
=
0.60
×
37
0.40
×
119
+
0.60
×
37
Y
t
=
0.318
b
)
X
B
=
0.6
;
Y
B
=
0.6
×
119
0.6
×
119
+
0.60
×
37
=
0.829
;
Y
t
=
1.000
−
0.829
=
0.171
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0
Similar questions
Q.
Vapour pressure of pure benzene is
119
torr
and of toluene is
37.0
torr
at the same temperature. Then mole fraction of toluene in vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene
0.50
,
will be:
Q.
Calculate the mole fraction of toluene in the vapor phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of 0.5 (The vapor pressure of pure Benzene is 119 torr and that of toluene is 37 torr at the same temperature:
Q.
Calculate the mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene and toluene having a mole fraction of toluene 0.50. The vapour pressure of pure benzene is 119 torr; that of toluene is 37 torr at the same temperature. ( If the answer is
x
, then write
x
×
10
−
3
)(rounding off to 3 digits)
Q.
At
88
0
C
, benzene has a vapour pressure of 900 torr and toluene has a vapour pressure of 360 torr. What is the mole fraction of benzene in the mixture with toluene that will boil at
88
0
C
at 1 atm pressure, benzene -toluene from an ideal solution?
Q.
Benzene and toluene form an ideal solution. Vapour Pressure of pure benzene is 100 torr while that of pure toluene is 50 torr. If mole fraction of benzene in liquid phase is
1
3
, calculate the mole fraction of benzene in vapour phase.
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