What is the compound interest on a principal of Rs 5000 at the rate of 10% for 2 years?

Rs. 1100

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Rs. 1050

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Rs. 1000

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Rs.1155

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Solution

The correct option is B
Rs. 1050

A = P ${[1 + \frac{R}{100}]}^{n}$

Here, P = Rs 5000, R = 10%, n = 2 years.

So, A = 5000 ${[1 + \frac{10}{100}]}^{2}$ = Rs 6050

So, CI = Rs 6050 - Rs 5000 = Rs. 1050

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What is the compound interest on a principal of Rs 5000 at the rate of 10% for 2 years?

The correct option is B Rs. 1050 A = P [1+R100]n Here, P = Rs 5000, R = 10%, n = 2 years. So, A = 5000 [1+10100]2 = Rs 6050 So, CI = Rs 6050 - Rs 5000 = Rs. 1050

The correct option is B
Rs. 1050

A = P ${[1 + \frac{R}{100}]}^{n}$

Here, P = Rs 5000, R = 10%, n = 2 years.

So, A = 5000 ${[1 + \frac{10}{100}]}^{2}$ = Rs 6050

So, CI = Rs 6050 - Rs 5000 = Rs. 1050