Question

What is the compressibility factor (Z) for 0.02 mole of a van der Waals' gas at pressure of 0.1 atm. Assume the size of gas molecules is negligible
Given : $RT=20Latmmo{l}^{-1}$ and $a=1000atm{L}^{2}mo{l}^{-2}$

• A. 2
• B. 1
• C. 0.02
• D. 0.5

Answer 1

Answer: (D)

0.5

Compressibility factor i.e Z = PV/RT

So, according to van der waal's equation, a = PV2/n2

Substituting, a= 1000, P= 0.1 atm, n= 0.02 mol

we get v = 2