What is the concentration in molarity of lithium hydroxide prepared by dissolving $48.0$ grams of solid in sufficient water of make $250 m L$ of solution?

502 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8.03 M

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.00803 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.502 M

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $8.03 M$
Given, mass of lithium hydroxide $= 48 g$
No. of moles of lithium hydroxide $= \frac{48}{24} = 2 m o l e s$
Given, volume of solution $= 250 m L$
So, Molarity $\frac{No. of moles}{Volume (in L)} = \frac{2}{0.25 L} = 8 M$

Suggest Corrections

Similar questions

49 g

H_{2} S O_{4}

250 m L

1

24.5 g

1 L

N a O H

Molarity of NaOH in a solution prepared by dissolving 4 g of NaOH in enough water to form 250 ml of solution is:

Join BYJU'S Learning Program