What is the concentration of a solution which contains 16 g of urea in 120 g of solution?

Open in App

Solution

Mass of solute = 16 g
Mass of solution = 120 g
Concentration of a solution = $\frac{M a s s o f S o l u t e}{M a s s o f S o l u t i o n}$ $\times$ 100 = $\frac{16}{120}$ $\times$ 100 = 13.33%

Suggest Corrections

307

Similar questions

Q. 255 g of an aqueous solution contains 5 g of urea. What is the concentration of the solution in terms of molality?
(Molar mass of urea = 60 g/mol)

Q. A solution contains 100 g of urea in 400 g of water. Calculate the concentration in terms of mass by mass percentage of the solution.

The concentration in gms per litre of a solution of cane sugar (M=342) which is isotonic with a solution containing 6 gms of urea (M = 60) per litre is:

Join BYJU'S Learning Program

What is the concentration of a solution which contains 16 g of urea in 120 g of solution?

Mass of solute = 16 g Mass of solution = 120 g Concentration of a solution = Mass of SoluteMass of Solution × 100 = 16120 × 100 = 13.33%

Mass of solute = 16 g
Mass of solution = 120 g
Concentration of a solution = $\frac{M a s s o f S o l u t e}{M a s s o f S o l u t i o n}$ $\times$ 100 = $\frac{16}{120}$ $\times$ 100 = 13.33%