Question

What is the concentration of an $NaOH$ solution if it takes $12.50mL$ of a $0.100MHCl$ solution to titrate $25.00mL$ of the $NaOH$ solution?

• A. $3.12M$
• B. $0.200M$
• C. $0.0500M$
• D. $0.0125M$

Answer 1

Answer: (C)

$0.0500M$

Moles of $O{H}^{-}=$ Moles of $H^{+}$

(Concentration of $NaOH$ solution) $\times$ (Volume of $NaOH$ solution) $=$ (Concentration of $HCl$ solution) $\times$ (Volume of $HCl$ solution)
$\therefore$ Concentration of $NaOH$ solution $=\frac{0.100\times 12.5}{25}=0.05$ $M$