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Question
What is the concentration of CO in equilibrium at 25oC in a sample of a gas originally containing 1.00 mol L−1 of CO2? For the dissociation of CO2 at 25oC.
Kc=2.96×10−92
Kc=2.96×10−92
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Solution
CO2(g)⇋2CO(g)+O2(g)
At equi.(1−2x) (2x) (x)
Applying law of mass action
Kc=[O2][CO]2[O2]2=2.96×10−92
It can be assumed that 1−2x=1.0 as Kc is very small.
So, 4x3=2.96×10−92
or x=1.956×10−31molL−1
[CO]=2x=3.90×10−31molL−1
At equi.(1−2x) (2x) (x)
Applying law of mass action
Kc=[O2][CO]2[O2]2=2.96×10−92
It can be assumed that 1−2x=1.0 as Kc is very small.
So, 4x3=2.96×10−92
or x=1.956×10−31molL−1
[CO]=2x=3.90×10−31molL−1
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