What is the concentration of $H^{+}$ in a solution that is prepared by mixing $50 m L$ of $0.5 M$ $H C l$ and $200 m L$ of $0.25 M$ $H C l$ ?

0.30 M

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0.35 M

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0.40 M

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0.45 M

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Solution

The correct option is C $0.30 M$
total molarity of a mixture of different concentrations of acid is given as
$M V = M_{1} V_{1} + M_{2} V_{2}$
$M_{1} = 0.5 M$
$V_{1} = 50 m l$
$M_{2} = 0.25 M$
$V_{2} = 200 m l$
Total volume is
$V = V_{1} + V_{2} = 50 + 200 = 250 m l$

$∴ M \times (250) = (0.5 \times 50) + (0.25 \times 200)$

$M = \frac{(25 + 50)}{250} = 0.3 M$

Hence, option $A$ is correct.

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