What is the concentration of nitrate ions if equal volumes of 0.1 M $A g N O_{3}$ and 0.1 M NaCl are mixed together

0.1 M

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0.2 M

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0.05 M

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0.25 M

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Solution

The correct option is C 0.05 M
$0.1 M A g N O_{3}$ will react with 0.1 M NaCl to form 0.1 M $N a N O_{3}$ . But as the volume is doubled, conc. of $N O_{3}^{-} = \frac{0.1}{2} = 0.05 M$

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Equal volumes of 0.1M $A g N O_{3}$ and 0.2 M NaCl are mixed together. The concentration of nitrate ions in the resulting mixture is:

Equal volumes of 0.1 M HCl and 0.1 M NaOH are mixed. The concentration of the resulting solution will be

a.0.1 M

b.0.05 M

c.0.2 M

d.0M

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