What is the concentration of nitrate ions if equal volumes of $0.1 M A g N O_{3}$ and $0.1 M N a C l$ are mixed together?

0.1

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0.2

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0.05

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0.25

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Solution

The correct option is C $0.05$ M
Given,

$0.1 M$ $A g N O_{3}$ & $0.1 M$ $N a C l$ are mixed together.

We know,

$0.1 M$ $A g N O_{3}$ solution contains

$0.1$ moles of $A g^{+}$ & $0.1$ moles of $N O_{3}^{-}$ in $1000 m l$ of solution.

$0.1 M$ $N a C l$ solution contains

$0.1$ moles of $N a^{+}$ & $0.1$ moles of $C l^{-}$ ions in $1000 m l$ of solution.

$∴$ Total moles of $N O_{3}^{-} = 0.1$

The total volume of solution= $2000 m l$

$∴$ Molarity of $N O_{3}^{-}$ ions= $\frac{m o l e s o f N O_{3}^{-}}{V o l u m e o f s o l u t i o n i n L}$

$= \frac{0.1 m o l e s}{2 L}$

$= 0.05 M$ .

Hence, the correct option is $C$

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