What is the concentration of $N O_{3}^{-}$ ions when equal volumes of $0.1 M A g N O_{3}$ and $0.1 M N a C l$ are mixed together?

0.1 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.25 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.05 N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.2 N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $0.05 N$
$A g N O_{3} (a g) + N a C l (a g) \to A g C l (s) + N a N O_{3} (a g)$

As per equation, nitrate ions remain unaffected

As volume has doubled after mixing, therefore the concentration of $N O_{3}$ ions will be reduced

$∴ \frac{0.1}{2} = 0.05 M$

Hence, the correct option is $C$

Suggest Corrections

Similar questions

0.1 M A g N O_{3}

0.1 M N a C l

What is the concentration of NO3- ions when equal volume of 0.1M AgNO3 and 0.1M NaCl are mixed together?

A g N O_{3}

Equal volumes of 0.1M AgNO₃and 0.2M NaCl are mixed. The concentration of NO^-₃ ions in the mixture will be

0.1 M A g N O_{3}

0.2 M N a C l

N O_{3}^{-}

Join BYJU'S Learning Program