What is the concentration of NO3- ions when equal volume of 0.1M AgNO3 and 0.1M NaCl are mixed together?

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Solution

0.1M AgNO3 contains 0.1mole of NO−3ions in 1 L of solution. 0.1M AgNO3 will react with 0.1 M NaCl to form 0.1 M NaNO3. Here the quantity of NO−3 is same but the volume is doubled due to addition of 0.1mole NaCl.The volume of the solution is double we know that concentration is inversely proportional to volume. When volume is doubled means concentration will be halved.

So required concentration = 0.1/2=0.05 M

Answer : 0.05 M

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