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Question

What is the concentration of O2 in a fresh water stream in equilibrium with air at 25o C and 1.0 bar ?
Given that , at 1 bar oxygen in air is 21% by volume
KH (Henry's law constant) for O2=1.3×103 mol/kg bar at 25o C.

A
8.736×103 g/kg
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B
4.16×102 g/kg
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C
24.04 g/kg
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D
114.5 g/kg
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Solution

The correct option is A 8.736×103 g/kg
In this case, KH has been given in the unit of mol/kg bar.
By Henry's law,
Solubility of O2 =KH Pgas
χO2 (in air) =21100=0.21
pO2=Pair×χO2=0.21 bar
Solubility=1.3×103molkg bar×0.21 bar
Solubility=2.73×104mol/kg=2.73×104×32 g/kg
Solubility=8.736×103 g/kg

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