Concentration of sugar
Given, 𝑀𝑎𝑠𝑠 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑒 =20 g
Molarmassofsolute(C12H22O11)=12×12+22×1+11×16=342 g/mol
𝑉𝑜𝑙𝑢𝑚𝑒 𝑜𝑓 𝑠𝑜𝑙𝑢𝑡𝑖𝑜𝑛 (inL)=2
We know,
Molarity(M)=Number of moles of soluteVolume of solution in liters
=MassofsugarMolarmassofsugar2L
=20 g342 g2L
=0.02925 molL−1
Final answer: 𝑀𝑜𝑙𝑎𝑟 𝑐𝑜𝑛𝑐𝑒𝑛𝑡𝑟𝑎𝑡𝑖𝑜𝑛 =0.02925 mol L–1