What is the concentration of sugar $(C_{12} H_{22} O_{11})$ in $mol L^{- 1}$ if its $20$ g are dissolved in enough water to make a final volume up to $2 L$ ?

Open in App

Solution

$Molarity = \frac{Mass}{Molar mass \times Volume}$
The concentration of sugar $(C_{12} H_{22} O_{11})$ is $\frac{20}{342 \times 2} = 0.029 m o l / L$ .

$∵$ molar mass of $C_{6} H_{22} O_{11}$ =342

Suggest Corrections

Similar questions

What is the concentration of sugar (C₁₂H₂₂O₁₁) in mol L^–1 if its 20 g are dissolved in enough water to make a final volume up to 2 L?

(C_{12} H_{22} O_{11})

20

2

L^{- 1}

80 g

3 L

C_{12} H_{22} O_{11}

C_{12} H_{22} O_{11}

40

Join BYJU'S Learning Program