wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the condition for a strictly increasing differentiable function?


A

f’(x) > 0

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

f’(x) ≥ 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

f’(x) < 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

f’(x) ≤ 0

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

f’(x) > 0


We can answer this question in the same way how we answered the condition for monotonically increasing function. Let’s assume we have a function f(x) which is differentiable throughout its domain.

Let’s take two points which are in the domain of f(x). Let them be a & b, such that b > a.

It is given that function is strictly increasing, so f(b) > f(a).

Let’s assume there is a point c, such that c (a , b)

Now, with the mean value theorem we can say that

f’(c) =

Or f’(c) (b- a) = f(b) - f(a)

Or f’(c) (b- a) > 0 as we know that f(b) > f(a)

Or f’(c) > 0 as b > a

Here, ‘c’ was some random point between the points a & b which are again random points.

So in a general way we can say that f’(x) > 0.


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon