What is the condition for a strictly increasing differentiable function?
f’(x) > 0
We can answer this question in the same way how we answered the condition for monotonically increasing function. Let’s assume we have a function f(x) which is differentiable throughout its domain.
Let’s take two points which are in the domain of f(x). Let them be a & b, such that b > a.
It is given that function is strictly increasing, so f(b) > f(a).
Let’s assume there is a point c, such that c ∈ (a , b)
Now, with the mean value theorem we can say that
f’(c) =
Or f’(c) (b- a) = f(b) - f(a)
Or f’(c) (b- a) > 0 as we know that f(b) > f(a)
Or f’(c) > 0 as b > a
Here, ‘c’ was some random point between the points a & b which are again random points.
So in a general way we can say that f’(x) > 0.