What is the condition for Cauchy-Schwarz Inequality?

\frac{a_{1}}{b_{1}} \neq \frac{a_{2}}{b_{2}} \neq . . . . . . .

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\frac{a_{1}}{b_{1}} = \frac{a_{2}}{b_{2}} = . . . . .

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\frac{a_{1}}{b_{1}} + \frac{a_{2}}{b_{2}} + . . . . . . . . = 0

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\frac{a_{1}}{b_{1}} - \frac{a_{2}}{b_{2}} - . . . . . . . . . = 0

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Solution

The correct option is B $\frac{a_{1}}{b_{1}} = \frac{a_{2}}{b_{2}} = . . . . .$
Cauchy Schwarz inequality holds only when
$\frac{a_{1}}{b_{1}} = \frac{a_{2}}{b_{2}} = . . . . . . . . . . . . . . . . = \frac{a_{k}}{b_{k}}$

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What is the condition for Cauchy-Schwarz Inequality?

The correct option is B a1b1=a2b2=.....Cauchy Schwarz inequality holds only when a1b1=a2b2=................=akbk

The correct option is B $\frac{a_{1}}{b_{1}} = \frac{a_{2}}{b_{2}} = . . . . .$
Cauchy Schwarz inequality holds only when
$\frac{a_{1}}{b_{1}} = \frac{a_{2}}{b_{2}} = . . . . . . . . . . . . . . . . = \frac{a_{k}}{b_{k}}$