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Question

What is the correct equilibrium expression (Ksp) for the reaction below:
Ca3(PO4)2(s) ⇌ 3Ca2+(aq) + 2PO42-(aq)


A

Ksp = [3Ca2+][2PO43-]

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B

Ksp = [Ca2+]3 [PO43-]2

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C

Ksp = [3Ca2+] + [2PO43-]

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D

Ksp = [3Ca2+]3 + [2PO43-]2

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Solution

The correct option is B

Ksp = [Ca2+]3 [PO43-]2


Ksp = [Ca2+]3[PO43-]2


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