wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

What is the correct expression of the standing wave equation?

A
(0.1)sin(π/2)xsin(10π)t
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
(0.1)sin(π)xsin(10π)t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
(0.05)sin(π/2)xcos(10π)t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
(0.04)sin(π/)xsin(10π)t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A (0.1)sin(π/2)xsin(10π)t
μ=1.22=0.6 kg/m
f=5 Hz,λ=2l=4 m
v=nλ=5×4=20 m/s
Using: v=TmuT=202×0.6=240 N
(yt)max=3.14 m/s
(2A)ω=3.14
Amplitude, 2A=3.142×3.14×5=0.1 m
Equation of standing wave is: y=0.1sin(π/2)×sin(10π)t

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Surfing a Wave
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon