What is the correct order of decreasing stability of the carbocations?

I I > I > I I I

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I I > I I I > I

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I I I > I > I I

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I > I I > I I I

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Solution

The correct option is A $I I > I > I I I$

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Similar questions

Arrange the following carbocations in decreasing order of stability

^{\oplus} C H_{2} - C O C H_{3}

^{\oplus} C H_{2} - O C H_{3}

^{\oplus} C H_{2} - C H_{3}

The correct order for decreasing stability of the following free radicals is

I V > I I I > I I > I

I V > I I I > I > I I

I V > I > I I > I I I

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