You visited us 5 times! Enjoying our articles? Unlock Full Access!

Graham's Law of Effusion

What is the c...

Question

What is the correct relationship between the pHs of isomolar solutions of sodium oxide $(p H_{1}),$ sodium sulphide $(p H_{2}),$ sodium selenide $p H_{3})$ and sodium telluride $p H_{4})$ ?

p H_{1} > p H_{2} \approx p H_{3} > p H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p H_{1} < p H_{2} < p H_{3} < p H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p H_{1} < p H_{2} < p H_{3} \approx p H_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

p H_{1} > p H_{2} > p H_{3} > p H_{4}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $p H_{1} > p H_{2} > p H_{3} > p H_{4}$
Acidic character increases in the order
$H_{2} O < H_{2} S < H_{2} S e < H_{2} T e$
Basic character of conjugate bases will be in the order
$O^{2 -} > S^{2 -} > S e^{2 -} > T e^{2 -}$
More the basic character, more the pH
$∴$ pHs are in the order
$p H_{1} > p H_{2} > p H_{3} > p H_{4} .$

Suggest Corrections

Similar questions

(p H_{1})

(p H_{2})

(p H_{3})

(p H_{4})

p H

p H_{1}

p H_{2}

p H_{3}

p H_{4}

p H = (p H)_{1}

p H = (p H)_{2}

(p H)_{2} - (p H)_{1} =

(p H)_{1} + (p H)_{2} = 9.5 u n i t s

P h_{3} ¨ ⊖ C

P h_{2} ¨ ⊖ C H

P h ¨ ⊖ C H_{2}

P H_{3} + \oplus N H_{4} ⟶ \oplus P H_{4} + N H_{3}

N H_{3} + P {\oplus H}_{4} ⟶ N {\oplus H}_{4} + P H_{3}

(C H_{3})_{3} P + \oplus N H_{4} ⟶ (C H_{3})_{3} \oplus P H + N H_{3}

(C H_{3})_{3} N + P H_{4}^{\oplus} ⟶ (C H_{3})_{3} \oplus N H + P H_{3}

Join BYJU'S Learning Program