What is the correct sequence of reagents used for coverting nitrobenzene into m-dibromobenzene?

N a N O_{2} ⟶ / H C l ⟶ / K B r ⟶ /^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

S n / H C l ⟶ / B r_{2} ⟶ / N a N O_{2} ⟶ / N a B r ⟶

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B r_{2} / F e ⟶ / S n / H C l ⟶ / N a N O_{2} / H C l ⟶ / C u B r / H B r ⟶

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

S n / H C l ⟶ / K B r ⟶ / B r_{2} ⟶ /^{+}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $B r_{2} / F e ⟶ / S n / H C l ⟶ / N a N O_{2} / H C l ⟶ / C u B r / H B r ⟶$
First step is the bromination of nitrobenzene, $N O_{2}$ is a meta directing group so meta-bromo product is formed. Second step is reduction of $- N O_{2}$ to $- N H_{2}$ group by $S n / H C l$ reagent. In third step, amine undergoes diazotisation reaction to give diazonium salt followed by reaction with CuBr to give the desired product.

Hence, option (d) is correct.

Suggest Corrections