What is the correct time in a clock between 7 and 8 p.m. when the two hands of clock are 5 mintues space apart?

7 - 32 \frac{4}{11} a n d 7 - 43 \frac{5}{11}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 - 32 \frac{8}{11} a n d 7 - 43 \frac{7}{11}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7 - 32 \frac{3}{11} a n d 7 - 43 \frac{2}{11}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

7 - 32 \frac{3}{11} a n d 7 - 43 \frac{5}{11}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $7 - 32 \frac{8}{11} a n d 7 - 43 \frac{7}{11}$
30×1211=32811
∴ Correct time = 7−32811
40×1211=43711
∴ Correct time = 7−43711

Suggest Corrections

Similar questions

-

-

{(\frac{6}{7})}^{3} \times {(\frac{6}{7})}^{5}

{(- \frac{3}{2})}^{5} \times {(- \frac{3}{2})}^{3}

a^{16} \times a^{7}

{(\frac{P}{5})}^{3} \times {(\frac{P}{5})}^{7}

Question 12

$(- 11) \times 7$ is not equal to

(a) $11 \times (- 7)$
(b) $- (11 \times 7)$
(c) $(- 11) \times (- 7)$
(d) $7 \times (- 11)$

\frac{\sqrt{11} - \sqrt{7}}{\sqrt{11} + \sqrt{7}} \times \frac{\sqrt{11} - \sqrt{7}}{\sqrt{11} - \sqrt{7}}

Join BYJU'S Learning Program