What is the correct unit of equilibrium constant $(K_{c})$ for the below reaction?
$C (s) + \frac{1}{2} O_{2} (g) ⇌ C O (g)$

(m o l / L)

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(m o l / L)^{\frac{3}{2}}

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(m o l / L)^{\frac{- 1}{2}}

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(m o l / L)^{\frac{1}{2}}

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Solution

The correct option is D $(m o l / L)^{\frac{1}{2}}$
Equilibrium constant $K_{c}$ is proportional to the active masses of the products and reactants.
$C (s) + \frac{1}{2} O_{2} (g) ⇌ C O (g)$
$For this reaction, K_{c} = \frac{[C O]}{[O_{2}]^{\frac{1}{2}}}$
Active mass of solids are considered as 1.
where $[C O]$ , $[O_{2}]^{\frac{1}{2}}$ are the molar concentations having a unit of mol/L
So, unit of $K_{c} = \frac{m o l / L}{(m o l / L)^{\frac{1}{2}}}$
$K_{c} = (m o l / L)^{\frac{1}{2}}$

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