What is the covalency of $O_{2}$ and $N_{2}$ molecules?

0,0

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1,2

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2,3

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3,3

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Solution

The correct option is C 2,3
The covalency of an atom is the number of electrons it shares with other atoms when forming chemical bonds. So covalency of oxygen is two as it forms a double bond and that of nitrogen is three as it forms a triple bond.

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Similar questions

How many covalent bonds are formed in $C l_{2,} O_{2}$ and $N_{2}$ molecules?

How many compounds are formed by covalency?

$K C l, N a C l, C s C l, O_{2}, N_{2}, C O_{2}, B a O, C a C l_{2}, H_{2} O$

What is the effect of the following processes on the bond order in $N_{2}$ and $O_{2}$ ?

(i). $N_{2} \to N_{2}^{+} + e^{-}$

(ii) $O_{2} \to O_{2}^{+} + e^{-}$

What is meant by the term bond order? Calculate the bond order of: $N_{2}$ , $O_{2}$ , $O_{2}^{+}$ and $O_{2}^{-}$ .

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H_{2}, N_{2}, O_{2}

H B r

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