What is the critical angle for a light ray going from dense glass into water ? The refractive index of glass and water relative to air are 1.62 and 1.33 respectively

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Solution

Dear Student,

$L e t t h e c r i t i c a l a n g l e b e c ° S o, u \sin g s n e l l' s l a w, w e c a n w r i t e \frac{\sin c °}{\sin 90 °} = \frac{1.33}{1.62} = > \sin c ° = \frac{1.33}{1.62} = 0.82 = > c ° = \sin^{- 1} (0.82)$

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What is the critical angle for a light ray going from dense glass into water ? The refractive index of glass and water relative to air are 1.62 and 1.33 respectively

Dear Student, Let the critical angle be c°So, using snell's law, we can writesin c°sin 90° = 1.331.62=> sin c°= 1.331.62 = 0.82=> c° = sin-1(0.82) Regards

Dear Student,

$L e t t h e c r i t i c a l a n g l e b e c ° S o, u \sin g s n e l l' s l a w, w e c a n w r i t e \frac{\sin c °}{\sin 90 °} = \frac{1.33}{1.62} = > \sin c ° = \frac{1.33}{1.62} = 0.82 = > c ° = \sin^{- 1} (0.82)$

Regards