Question

What is the cube root of $\left[\right(-27)\times 8]$?

• A. - 6
• B. 6
• C. - 12
• D. 12

Answer 1

The correct option is A - 6

$\sqrt[3]{3(-27\times 8)}=\sqrt[3]{3(-27)}\times \sqrt[3]{38}$
$=\sqrt[3]{3(-3)\times (-3)\times (-3)}\times \sqrt[3]{32\times 2\times 2}$
$\downarrow$ $\downarrow$
$(-3)$ $\left(2\right)$
$=(-3)\times \left(2\right)=-6$
So, the option (1) is correct.