Question

What is the current in circuit shown below

Answer 1

$\frac{1}{R_{\mu }}=\frac{1}{2}+\frac{1}{4}$

$\frac{1}{R_{\mu }}+\frac{3}{4}$

$R_{eq}=\frac{4}{3}$

V = iR

i = $\frac{V}{R}$

$=\frac{2}{\frac{4}{3}}$

$=\frac{3}{2}=$ 1.5 Amp