What is the current through the voltmeter if it has a coil resistance of 100k- series resistance of 1k- and 202V is measured by it-

In accordance with Ohm’s law, V=IR, Given, V=202 V R_eq=(100+1)k Ω = 101 k Ω I=V/R_eq=202/101000A=2mA ...

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Physics

Voltmeter

What is the c...

Question

What is the current through the voltmeter if it has a coil resistance of 100k $Ω$ , series resistance of 1k $Ω$ and 202V is measured by it?

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20mA

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2mA

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2.02A

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Solution

The correct option is C 2mA
In accordance with Ohm’s law,
V=IR,
Given,
V=202 V
$R_{e q} = (100 + 1) k Ω = 101 k Ω I = \frac{V}{R_{e q}} = \frac{202}{101000} A = 2 m A$

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What is the current through the voltmeter if it has a coil resistance of 100kΩ, series resistance of 1kΩ and 202V is measured by it?

The correct option is C 2mAIn accordance with Ohm’s law, V=IR, Given, V=202 V Req=(100+1)kΩ=101kΩI=VReq=202101000A=2mA

What is the current through the voltmeter if it has a coil resistance of 100k $Ω$ , series resistance of 1k $Ω$ and 202V is measured by it?

The correct option is C 2mA
In accordance with Ohm’s law,
V=IR,
Given,
V=202 V
$R_{e q} = (100 + 1) k Ω = 101 k Ω I = \frac{V}{R_{e q}} = \frac{202}{101000} A = 2 m A$