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Question

What is the de Broglie wavelength of (a) a bullet of mass 0.040 kg travelling at the speed of 1.0 km/s, (b) a ball of mass 0.060 kg moving at a speed of 1.0 m/s, and (c) a dust particle of mass 1.0 × 10–9 kg drifting with a speed of 2.2 m/s?

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Solution

a)

Given: the mass of the bullet is 0.040kg, the speed of the bullet is 1.0km/s.

de Broglie wavelength of the bullet is given as,

λ= h mυ

Where, the mass of bullet is m, the de Broglie wavelength of bullet is λ, the speed of the bullet is υ, Planck’s constant is h.

Since, 1km=1000m.

By substituting the given values in the above formula, we get

λ= 6.63× 10 34 0.040×1000 =1.65× 10 35 m

Thus, de Broglie wavelength of bullet is 1.65× 10 35 m.

(b)

Given: the mass of the ball is 0.060kg, the speed of the ball is 1.0m/s.

de Broglie wavelength of the bullet is given as,

λ= h mυ

By substituting the given values in the above formula, we get

λ= 6.6× 10 34 0.060×1 =1.1× 10 32 m

Thus, de Broglie wavelength of ball is 1.1× 10 32 m.

c)

Given: the mass of the dust particle is 1× 10 9 kg, the speed of the dust particle is 2.2m/s.

de Broglie wavelength of the bullet is given as,

λ= h mυ

By substituting the given values in the above formula, we get

λ= 6.6× 10 34 2.2×1× 10 9 =3.0× 10 25 m

Thus, de Broglie wavelength of dust particle is 3.0× 10 25 m.


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