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Standard XII
Chemistry
Reactivity with Halogens and Hydrogen (Group 2)
what is the d...
Question
what is the decreasing order of second ionization enthalpy of Titanium chromium and manganese
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Q.
The atomic number of Vanadium
(
V
)
, chromium
(
C
r
)
, manganese
(
M
n
)
and iron
(
F
e
)
are respectively
23
,
24
,
25
and
26
. Which one of these may be expected to have the highest second ionization enthalpy?
Q.
The atomic number of vanadium (V), chromium (Cr), manganese (Mn) and iron (Fe) are respectively 23, 24, 25 and 26 which one of these may be expected to have the highest second ionization enthalpy
Q.
The atomic number of vanadium (V), chromium (Cr), manganese (Mn) and iron are respectively : [23, 24, 25 and 26]
Which one of these may be expected to have the highest second ionization enthalpy?
Q.
The correct order of decreasing second ionization enthalpy of is:
(
T
i
=
22
,
V
=
23
,
C
r
=
24
,
M
n
=
25
)
Q.
Give reasons:
Third ionization enthalpy of manganese is unusually high.
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