Question

What is the density of a nucleus of mass number $A$?

• A. $\frac{4}{3}\pi {(1.5\times {10}^{-15})}^3$
• B. $1.17\times {10}^{17}g/{cm}^3$
• C. $1.17\times {10}^{-17}kg/m^3$
• D. none of these

Answer 1

The correct option is B $1.17\times {10}^{17}g/{cm}^3$

Density $=\frac{M}{V}=\frac{M}{\left(4/3\right)\pi r^3}=\frac{A}{\left(4/3\right)\pi R_0^{3}A}$

After putting the values we get density = $1.17\times {10}^{17}g/c{m}^3$