what is the density of $N_{2}$ gas at $227^{o} c$ and $5.00 a t m$ pressure ? $(R = 0.0821 a t m K^{- 1} {m o l}^{- 1})$

0.29 g / m l

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1.40 g / m l

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2.81 g / m l

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3.41 g / m l

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Solution

The correct option is D $3.41 g / m l$

Given,

$P = 5 a t m$
$T = 500 K$
$M = 28 g / m o l$
We know,

$ρ = \frac{P M}{R T}$

$ρ = \frac{5 \times 28}{0.0821 \times 500}$

$ρ = 3.41 g / m l$

Option $D$ is the correct answer

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what is the density of N2 gas at 227o c and 5.00 atm pressure ? (R=0.0821atm K−1 mol−1)

The correct option is D 3.41 g/mlGiven,P=5atmT=500KM=28 g/molWe know,ρ=PMRTρ=5×280.0821×500ρ=3.41g/mlOption D is the correct answer

what is the density of $N_{2}$ gas at $227^{o} c$ and $5.00 a t m$ pressure ? $(R = 0.0821 a t m K^{- 1} {m o l}^{- 1})$

The correct option is D $3.41 g / m l$

Given,

$P = 5 a t m$
$T = 500 K$
$M = 28 g / m o l$
We know,

$ρ = \frac{P M}{R T}$

$ρ = \frac{5 \times 28}{0.0821 \times 500}$

$ρ = 3.41 g / m l$

Option $D$ is the correct answer