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Question

# What is the density of wet air with 75% relative humidity at 1 atm and 300 K? Given :vapour pressure of H2O is 30 torr and average molar mass of air is 29 g molâˆ’1.

A

2.614 g/L

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B

0.96 g/L

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C

1.06 g/L

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D

1.164 g/L

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Solution

## The correct option is D 1.164 g/L % Relative Humidity = Partial Pressure of H2OVapour Pressure of H2O×100 75=PH2O30×100 PH2O=22.5 torr % of H2O in air = 22.5760×100⇒2.96 Molar mass of wet air = 29×97.04+2.96×18100⇒2814.16+53.28100⇒28.67 Density of wet air = PMRT=1×28.670.0821×300⇒1.164 gL

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