What is the diameter of a circle whose area is equal to the sum of the areas of two circles of diameters 10 cm and 24 cm ?
To find diameter of circle [ d1 ]
given diameter of 2nd circle= 10cm
radius [ r₂] = 5 cm
diameter of 2rd circle = 24 cm
radius [r₃] = 12 cm
ATQ
πr₁² =πr₂² + πr₃²
лr₁² = л(r₂² + r₃²)
лr₁²/л = (5)² +(12)²
r₁² = 25 + 144
r₁² = 169
r₁= √169
r₁ = 13 cm
diameter= 2r₁ = 2 x 13 = 26 cm