Question

What is the diameter of the spherical ball whose volume is $268.08{mm}^3$. (use $\pi =3.14$). Round off your answer to nearest whole number.

• A. $4$ mm
• B. $3$ mm
• C. $1$ mm
• D. $8$ mm

Answer 1

The correct option is D $8$ mm

Formula:

Volume of sphere$=\frac{4}{3}\pi r^3$

where,

$r=radius$

Given:

$volume=268.08m{m}^3$

Substituting the values in the given formula we get:

$268.08=\frac{4}{3}\pi r^3$

$\Rightarrow 268.08=\frac{4}{3}\times 3.14\times r^3$

$\Rightarrow \frac{268.08\times 3}{4\times 3.14}=r^3$

$\Rightarrow r^3=\frac{804.28}{12.56}$

$\Rightarrow r^3=64.03\approx 64$

$\Rightarrow r=\sqrt[3]{364}$

$\Rightarrow r=4mm$

Thus, the diameter $=2r=8mm$.