What is the difference between the compound interest and simple interest accrued on an amount of 12000 at the end of three years at rate of 12%

539.136

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602.242

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495.248

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488.322

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Solution

The correct option is A 539.136
$P = 12000$
$T = 3$
$R = 12$ %

$S I = \frac{P T R}{100}$

$= \frac{12000 \times 3 \times 12}{100}$

$S I = R s .4320$

$C . I = P {(1 + \frac{R}{100})}^{T} - P$

$= 12000 {(1 + \frac{12}{100})}^{3} - 12000$

$= 12000 {(\frac{28}{25})}^{3} - 12000$

$C I = 4859.136$

$∴ C . I - S . I = R s (4859.136 - 4320)$

$= R s .539 .136$

$A n s : 539.136$

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What is the difference between the compound interest and simple interest accrued on an amount of 12000 at the end of three years at rate of 12%

The correct option is A 539.136P=12000T=3R=12%SI=PTR100 =12000×3×12100 SI=Rs.4320C.I=P(1+R100)T−P =12000(1+12100)3−12000 =12000(2825)3−12000 CI=4859.136∴C.I−S.I=Rs(4859.136−4320) =Rs.539.136Ans:539.136