What is the direction of net osmotic movement of water of a solution $A$ enclosed in a semipermeable membrane having an osmotic potential $- 30$ bars and pressure potential $5$ bars is surrounded in a solution $B$ of osmotic potential $- 10$ bars and pressure potential $= 0 ?$

A \to B

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B \to A

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No movement

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Equal amount

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Solution

The correct option is A $A \to B$
Water potential can be calculated as :
Water Potential = Solute Potential - Pressure Potential.
So, Water Potential for Cell A = -30 + 5 = -25
Water Potential for Cell B= -10 + 0 = -10
As Cell B has higher Water Potential, the water will move from Cell B to Cell A which has low Water Potential.
Hence, the correct answer is 'A to B'.

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What is the direction of net osmotic movement of water of a solution A enclosed in a semipermeable membrane having an osmotic potential −30 bars and pressure potential 5 bars is surrounded in a solution B of osmotic potential−10 bars and pressure potential=0?

What is the direction of net osmotic movement of water of a solution $A$ enclosed in a semipermeable membrane having an osmotic potential $- 30$ bars and pressure potential $5$ bars is surrounded in a solution $B$ of osmotic potential $- 10$ bars and pressure potential $= 0 ?$