What is the pH of a 0.5 M solution of acetic acid, if the Ka of acetic acid is 2×10−5?
A
1.0
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B
2.0
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C
2.5
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D
3.0
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E
7.0
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Solution
The correct option is C2.5 CH3COOH <---> CH3COO−+H+ Inital molarity 0.5 0 0 Equilibrium molarity 0.5-x x x Ka=2×10−5=x2(0.5−x) Because x is too small, so it can be ignored.