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Question

What is the pH of a 0.5 M solution of acetic acid, if the Ka of acetic acid is 2×105?

A
1.0
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B
2.0
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C
2.5
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D
3.0
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E
7.0
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Solution

The correct option is C 2.5
CH3COOH <---> CH3COO+H+
Inital molarity 0.5 0 0
Equilibrium molarity 0.5-x x x
Ka=2×105=x2(0.5x)
Because x is too small, so it can be ignored.

0.5x0.5

2×105=x20.5

x=0.003162

pH=log(0.003162)=2.5

Hence, the correct option is C.

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