What is the distance between two protons if the electrical repulsive force between them is equal to the weight of either proton

0.103 m

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0.102 m

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0.011 m

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0.118 m

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Solution

The correct option is
D

0.118 m

As we know, it is given that the force of repulsion is counter by gravitational force.
$∴ F_{n e t} = 0$
$F_{r e p u l} - m g = 0$
$F_{r e p u l} = m g$

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