What is the distance travelled by an object moving with a uniform acceleration in the interval between $t = 4$ and $t = 5$ seconds.
Given: initial velocity $= u$ , acceleration $= a$ .

u + 4.5 a

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u + 9 a

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u - 4.5 a

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u - 9 a

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Solution

The correct option is C $u + 4.5 a$
Displacement after $5 s$ is: $s_{5} = u t + 0.5 a t^{2} = 5 u + 0.5 \times 25 a$
Displacement after $4 s$ is: $s_{4} = u t + 0.5 a t^{2} = 4 u + 0.5 \times 16 a$
Distance covered in time-interval of $4 s$ to $5 s$ is: $s_{5} - s_{4} = u + 4.5 a$

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What is the distance travelled by an object moving with a uniform acceleration in the interval between t=4 and t=5 seconds. Given: initial velocity =u, acceleration =a.

The correct option is C u+4.5aDisplacement after 5 s is: s5=ut+0.5at2=5u+0.5×25aDisplacement after 4 s is: s4=ut+0.5at2=4u+0.5×16aDistance covered in time-interval of 4 s to 5 s is: s5−s4=u+4.5a

What is the distance travelled by an object moving with a uniform acceleration in the interval between $t = 4$ and $t = 5$ seconds.
Given: initial velocity $= u$ , acceleration $= a$ .

The correct option is C $u + 4.5 a$
Displacement after $5 s$ is: $s_{5} = u t + 0.5 a t^{2} = 5 u + 0.5 \times 25 a$
Displacement after $4 s$ is: $s_{4} = u t + 0.5 a t^{2} = 4 u + 0.5 \times 16 a$
Distance covered in time-interval of $4 s$ to $5 s$ is: $s_{5} - s_{4} = u + 4.5 a$