What is the distribution of electrons in a boron atom?

(2, 6)

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(2, 3)

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(2, 8)

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(2, 4)

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Solution

The correct option is C (2, 3)
The total number of electrons present in Boron atom is 5.
The distribution of electrons in oxygen atom is given by:
First orbit or K shell $= 2 (2 n^{2} = 2 \times 1^{1} = 2)$
Second orbit or L shell $= 3 (5 - 2 = 3)$

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